Experiment No . 2 ( B.Sc. 1 Semester Physics Project file )

 Experiment No. 2

Object 

      To determine the moment of Inertia of an inregular rigid body about an axis passing through its centre of gravity & perpendicular to its plane by dynamical method ( Inertia table ).

Apparatus Required  

                        Inertia table inregular body whose moment of inertia is to be determine , regular body whose moment of inertia can be calculated by majoring its dimenations & mass , stopwatch , sprit level physical balance with wait box & vernier calipers .

Formula Used

The moment of inertia I1 ( आई वन ) of the inregular body is determine with the help of following formula –

• Where I2 ( I tow ) is moment of Inertia of the regular body 
•   To is time period of inertia table .
• T1 ( T one ) is time period with the inregular body on the inertia table .
  
  
  

If the regular body is disc then –

Where M is mass of the disc & R is radius of the disc.

Observation table -

For without mass –

S. No.	No. of oscillation	Time t (sec)	Total time period	Mean ( sec ) ( To )
1.	10	123	12.3	62.3/5
2.	15	182	12.1
3.	20	262	13.1	= 12.46
4.	25	313	12.5
5.	30	310	12.3

 

2. For regular body mass = 560, radius = 4.375 cm

S .No .	No . of oscillation	Time t (sec)	Time period	Mean ( sec ) (T1)
1.	10	109	10.9	57.5/5
2.	15	111	11.4
3.	20	232	11.6	= 11.5
4.	25	294	11.7
5.	30	357	11.9

 

Calculation  the moment of inertia of inregular rigid body -

3 . For Inregular body -  

S .No.	No. of oscillation	Time (t) sec	Time period	Mean (sec) T2
1.	10	123	12.3	61.3/5
2.	15	184	12.2
3.	20	246	12.3	= 12 .26
4.	25	308	12.3
5.	30	368	12.2

 

Result –

            Moment of inertia of inregular body is 0.2490 kg/miter equare

Source of error & Precautions

1.      The inertia table should set horigental.

2.      The table should be rotted by a few degree only.

3.      Periodic time should be noted very carefully.

4.      There should not be any rink in the wire .

5.      There should not be any up & down as well as joo & fro motion of the table.

Note.

(Please note: if a particular experiment is not visible, please search for it using the search box—for example, Experiment No. 3.)

कृपया ध्यान दीजिये जो एक्सपेरिमेंट न दिख रहा हो वो आप सर्च बॉक्स में सर्च कर लीजिये . जैसे , एक्साप्रिमेंट नंबर.3

Experiment No . 3 ( B.Sc. 1 Semester Physics Project file )

         Experiment No. 3

Object

                To study the variation of T with L for a bar pendulum ( Compound Pendulum ) & then to determine –

1.       The value of accerleration due to gravity ( g ) in the labouratery .

2.       The position of centre of gravity of a bar .

Radius of gyration K of the bar about an axis passing through CG & perpendicular to its length .

Apparatus Required –

                Bar pendulum , stopwatch , meter scale & knife edge find to a rigid support .

Formula used –

                The value of g can be calculated with the help of following formula –

Where , L distance between centers of oscillation & suspetions T is periodic table .

Observation table

S. No.	No. of hale	No. of iscillation	Distance of hale	Time (t) sec	Total time t/20
1.	1	20	5	31.57	1.5785
2.	2	20	10	31.58	1.583
3.	3	20	15	30.89	1.5445
4.	4	20	20	30.28	1.514
5.	5	20	25	30.69	1.5345
6.	6	20	30	31.39	1.5695
7.	7	20	35	33.71	1.6855
8.	8	20	40	38.66	1.933
9.	9	20	45	52.58	2.629

 

S. No.	No.of hale	No. of oscillation	Distance of hale	Time (t)	Total time t/20
1.	1	20	5	31.39	1.5695
2.	2	20	10	30.79	1.5395
3.	3	20	15	30.31	1.5155
4.	4	20	20	30.20	1.51
5.	5	20	25	29.98	1.49
6.	6	20	30	30.08	1.504
7.	7	20	35	33.57	1.6785
8.	8	20	40	39.76	1.988
9.	9	20	45	56.98	2.849

 

Calculation 

Position of C.G the bar pendulum      

                                                The distance of C.G of the bar from the end from where all the distance have been measured.

The radius of gyration (K)

                                From distance of the bar

                                                                                K = L/√2

                Where L = Length of bar

                                                                K = 1/1.414          = 0.707213578 miter

Result

                The value of g is 10.67012 miter/ sec square & the radius of gyration is 0.707213578 miter

Source of Error

1.       The knife edge should be horigentel & should be placed in the groove made on horigentel

2.       Amplitude of oscillation should be small.

3.       The time should recorded when the swings are regular.

4.       Vibration of pendulum should be vertical plane.

Note.

(Please note: if a particular experiment is not visible, please search for it using the search box—for example, Experiment No. 3.)

कृपया ध्यान दीजिये जो एक्सपेरिमेंट न दिख रहा हो वो आप सर्च बॉक्स में सर्च कर लीजिये . जैसे , एक्साप्रिमेंट नंबर.3